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1/3^x-3=9
We move all terms to the left:
1/3^x-3-(9)=0
Domain of the equation: 3^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/3^x-12=0
We multiply all the terms by the denominator
-12*3^x+1=0
Wy multiply elements
-36x+1=0
We move all terms containing x to the left, all other terms to the right
-36x=-1
x=-1/-36
x=1/36
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